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KevinLikesCoding ♀
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2050
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格言
$\pi(n)=dp_{n,\pi(n^\frac{1}{3})}-\pi(n^\frac{1}{3})+1 -\sum_{p\in (n^\frac{1}{3},n^\frac{1}{2}]} \pi(\frac{n}{p})-\pi(p)+1$
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Name | Start time |
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The 3rd Universal Cup. Stage 37: Wuhan | 2025-05-28 18:00:14 |
The 2021 ICPC Asia Shanghai Regional Contest | 2025-05-14 14:45:25 |