You fly away so proudly, away from my summer. Slient words of praying, all these years repeating
#327: KafuuChinocpp
Accepted: : 145
#327: Rong7
Accepted: : 145
We all get knocked down, but the measure of our character is how quickly we get back up.
#327: ucup-team1231
Accepted: : 145
#327: ucup-team2796
Accepted: : 145
#332: jrjyy
Accepted: : 144
#332: lichenyu_ac
Accepted: : 144
#332: lllei
Accepted: : 144
#332: MatrixGroup
Accepted: : 144
どうか どうか どうか | 可是真实的人生,必定是单调、残酷,而缺乏色彩的
#336: ucup-team3807
Accepted: : 143
无
#336: XY_Eleven
Accepted: : 143
#338: enze114514
Accepted: : 142
空を見上げて、空を見つめて、空を楽しんで、答えはそこにある。
#338: ucup-team6275
Accepted: : 142
#340: ucup-team162
Accepted: : 141
#341: ucup-team2008
Accepted: : 140
#342: nanika
Accepted: : 139
#342: PHarr
Accepted: : 139
One day I`ll be fearless.
#344: NOI_AK_ME
Accepted: : 138
爱思接外斜杠接外 如因博欧爱思接外 安普提厚普爱思接外 付鹅体科四一二三四五六爱思接外 爱思接外!
#345: frankly6
Accepted: : 137
#345: hutality
Accepted: : 137
$$[x^n](1-x)^{-\frac{1}{2}} \exp\left(\frac{x(1+x)}{2-2x}\right)\frac{\left(\frac{2-x}{2-2x}\right)^k}{k!}\cdot\,_0 F _1 \left(;k+1;x\left(\frac{2-x}{2-2x}\right)^2\right)$$
#345: LFAIJ
Accepted: : 137
誰のために希望描こう?
#345: minhcool
Accepted: : 137
Glory Glory HUS HSGS
#349: Minneapolis
Accepted: : 136
卷王别卷了
#349: ucup-team139
Accepted: : 136
#349: ucup-team4740
Accepted: : 136
#349: YaoBIG
Accepted: : 136
#353: goodman
Accepted: : 135
#353: ucup-team254
Accepted: : 135
#355: ANIG
Accepted: : 134
..
#355: haze
Accepted: : 134
爱在一起或死在一起,舍此别无他途。
#355: mekoszc
Accepted: : 134
#355: triplem5ds
Accepted: : 134
#355: ucup-team2016
Accepted: : 134
#360: Beevo
Accepted: : 133
#360: i_am_noob
Accepted: : 133
#360: InfinityNS
Accepted: : 133
#360: juan_123
Accepted: : 133
#360: QZJ123456
Accepted: : 133
点赞过三万更新狗鲸鱼写真集
#360: ucup-team154
Accepted: : 133
#360: ucup-team2303
Accepted: : 133
#367: crsfaa
Accepted: : 132
#367: liuziao
Accepted: : 132
#367: lwm7708
Accepted: : 132
https://lwm7708.github.io/entropy/
#370: BreakPlus
Accepted: : 131
#370: eastcloud
Accepted: : 131
#370: LH
Accepted: : 131
$$|X/G| = \frac{1}{|G|}\sum_{g \in G}|X^g|$$
#370: ucup-team1348
Accepted: : 131
#374: ucup-team1264
Accepted: : 130
#374: ucup-team2279
Accepted: : 130
#374: ucup-team241
Accepted: : 130
#374: ucup-team3665
Accepted: : 130
#374: ucup-team881
Accepted: : 130
simple whales
#374: wxhtzdy
Accepted: : 130
#380: ucup-team3282
Accepted: : 129
#380: ucup-team3502
Accepted: : 129
#382: Calculatelove
Accepted: : 128
Love all my perfect imperfections.$\textrm{Make FZU great again!}$
#382: ucup-team1704
Accepted: : 128
#382: ucup-team1876
Accepted: : 128
#382: ucup-team3555
Accepted: : 128
In the changing arena,Zhicheng is the top of the algorithm.Code weaves into a winning net,Wisdom flowers bloom in spring.